Interview Puzzles

Stack of 'must-know' interview puzzles !
<< Previous || Next >>

Puzzle: Life full of Managers!

3106 views

An official meeting is going on in a conference hall room.
There are 100 employees in that room. 
Out of that 99% are managers. 
How many managers must leave the room to bring down the percentage of managers to 98%?

12 Vote Up   |   Post Answer   |   View Solution

By  Shaan





Roshan Singh Roshan Singh   5 years ago

Given:
Number of Employees = 100
Number of Managers = 99% = 99
Number of non-managers = 100 - 99 = 1
Now, Let there be x employees remaining so that managers = 98%
Therefore, non-managers = 100 - 98 = 2%
Also non-managers count didn't change, so = 2% = 1
Which implies => 2% of x = 1
2x = 100
x = 50
Which means number of managers = 50 - 1 = 49
So, number of managers who left the room = 99 - 49 = 50

Reply    15 Vote Up   0 Vote Up


Chirag Kansal Chirag Kansal   4 years ago

Suppose total persons : 100
So managers are 99% means 99 only 1 person is non manager

if a manager left one by one then

Then when half of the managers left(50) then percentage of the mangers become become 98%

49/50 = .98%

Reply    2 Vote Up   0 Vote Up


BIBEKANANDA CHELLENG BIBEKANANDA CHELLENG   4 years ago

50 managers/

Reply    0 Vote Up   0 Vote Up


PATAN SADDAM PATAN SADDAM   6 months ago

2

Reply    0 Vote Up   0 Vote Up


Ankit Ankit   6 months ago

50

Reply    0 Vote Up   0 Vote Up


Sooraj Dwivedi Sooraj Dwivedi   6 months ago

50

Reply    0 Vote Up   0 Vote Up


Nitin Gupta Nitin Gupta   2 months ago

50

Reply    0 Vote Up   0 Vote Up